Women's singles | |
---|---|
1939 U.S. National Championships | |
Champion | ![]() |
Runner-up | ![]() |
Final score | 6–0, 8–10, 6–4 |
Draw | 64 |
Seeds | 8 |
First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–0, 8–10, 6–4 in the final to win the women's singles tennis title at the 1939 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 7, through September 17, 1939 at the West Side Tennis Club in Forest Hills, Queens, New York.[1][2]
The draw consisted of 64 players of which eight were seeded.
Seeds
The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.
Alice Marble (champion)
Helen Jacobs (finalist)
Sarah Fabyan (quarterfinals)
Dorothy Bundy (quarterfinals)
Gracyn Wheeler (first round)
Helen Bernard (third round)
Dorothy Workman (third round)
Virginia Wolfenden (semifinals)
Draw
Final eight
Quarterfinals | Semifinals | Finals | ||||||||||||||||||
2 | ![]() | 2 | 6 | 6 | ||||||||||||||||
![]() | 6 | 2 | 3 | |||||||||||||||||
2 | ![]() | 7 | 6 | |||||||||||||||||
![]() | 5 | 0 | ||||||||||||||||||
3 | ![]() | 6 | 3 | 3 | ||||||||||||||||
![]() | 1 | 6 | 6 | |||||||||||||||||
2 | ![]() | 0 | 10 | 4 | ||||||||||||||||
1 | ![]() | 6 | 8 | 6 | ||||||||||||||||
1 | ![]() | 6 | 6 | 6 | ||||||||||||||||
![]() | 3 | 8 | 2 | |||||||||||||||||
1 | ![]() | 6 | 6 | |||||||||||||||||
8 | ![]() | 0 | 1 | |||||||||||||||||
4 | ![]() | 6 | 1 | 2 | ||||||||||||||||
8 | ![]() | 2 | 6 | 6 |
References
- ^ a b Collins, Bud (2016). The Bud Collins History of Tennis (3rd ed.). New York: New Chapter Press. p. 498. ISBN 978-1-937559-38-0.
- ^ "Rigs defeats Van Horn". The Advocate. Tasmania, Australia. 19 September 1939. p. 3 – via National Library of Australia.